Inverse Matrix/3x3/7/Aufgabe/Lösung

${}{\begin{pmatrix}1&12&0\\3&0&1\\0&0&2\end{pmatrix}}$	${}{\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}}$
${}{\begin{pmatrix}1&12&0\\0&-36&1\\0&0&1\end{pmatrix}}$	${}{\begin{pmatrix}1&0&0\\-3&1&0\\0&0&{\frac {1}{2}}\end{pmatrix}}$
${}{\begin{pmatrix}1&12&0\\0&-36&0\\0&0&1\end{pmatrix}}$	${}{\begin{pmatrix}1&0&0\\-3&1&-{\frac {1}{2}}\\0&0&{\frac {1}{2}}\end{pmatrix}}$
${}{\begin{pmatrix}1&12&0\\0&1&0\\0&0&1\end{pmatrix}}$	${}{\begin{pmatrix}1&0&0\\{\frac {1}{12}}&-{\frac {1}{36}}&{\frac {1}{72}}\\0&0&{\frac {1}{2}}\end{pmatrix}}$
${}{\begin{pmatrix}1&0&0\\0&1&0\\0&0&1\end{pmatrix}}$	${}{\begin{pmatrix}0&{\frac {1}{3}}&-{\frac {1}{6}}\\{\frac {1}{12}}&-{\frac {1}{36}}&{\frac {1}{72}}\\0&0&{\frac {1}{2}}\end{pmatrix}}$

Zur gelösten Aufgabe